Second example: result is the same
In the following code,
assume that both unsigned short
and unsigned char
are narrower than int.
int f(void)
{
unsigned short us;
unsigned char uc;
return uc < us;
}
In this example,
both automatics are either promoted to int
or to unsigned int,
so the comparison is sometimes unsigned and sometimes signed.
However,
the ANSI C compiler will not warn you because the result
is the same for the two choices.